Question
A laser emits 1.42 1018 photons per second in a beam of light that has a diameter of 1.82 mm and a wavelength of 524.0 nm. Determine each of the following for the electromagnetic wave that constitutes the beam.
(a) the average electric field strength
(b) the average magnetic field strength
(a) the average electric field strength
(b) the average magnetic field strength
Answers
S=Energy per unit time/Area = Nhf/A= =4Nhc/πD²λ=
=4•1.42•10¹⁸•6.63•10⁻³⁴•3•10⁸/π•(1.82•10⁻³)²•524•10⁻⁹=
=2.07•10⁵ W/m²
Electric field
E= sqrt{S/(ε₀c)}=
= sqrt{2.07•10⁵/8.85•10⁻²•3•10⁸}=8834 N/C
Magnetic field
B=E/c =8834/3•10⁸ =2.94•10⁻⁵T
=4•1.42•10¹⁸•6.63•10⁻³⁴•3•10⁸/π•(1.82•10⁻³)²•524•10⁻⁹=
=2.07•10⁵ W/m²
Electric field
E= sqrt{S/(ε₀c)}=
= sqrt{2.07•10⁵/8.85•10⁻²•3•10⁸}=8834 N/C
Magnetic field
B=E/c =8834/3•10⁸ =2.94•10⁻⁵T
A laser emits a beam of light whose photons all have the same frequency. When the beam strikes the surface of a metal, photo-electrons are ejected from the surface. What happens if the laser emits twice the number of photons per second?
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