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Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.005 for two-tailed) and its Z score.
Mean for this group = 102
99% = mean ± Z(SEm)
SEm = SD/√n
You need to do the calculations.
It is known that the population mean for the Full Scale IQ of the WAIS is 100 with a standard deviation of 15. A researcher assesses a sample of 200 adults and find that they have a mean Full Scale IQ of 102. The point estimate of the mean for this group is ___________ and the 99% confidence interval for this group is ____________________.
a. 100; (97.27; 102.73)
b. 102; (97.27, 102.73)
c. 100; (99.27; 104.73)
d. 102; (99.27, 104.73)
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