Calculate the potential at 25∘C for a cell that has the following ion concentrations: [Ag+] = 1.0×10−2M , 3.2×10−2M .

Answer 1

Your post isn't very clear. Do you mean this is a concentration cell with one half cell of 1E-2M and the other 3.2E-2.
If so then Ecell = -(0.05916/1)log (dilute/concd)

Answer 2

Sorry!
Consider a galvanic cell that uses the reaction
2Ag+(aq)+Sn(s)→2Ag(s)+Sn2+(aq)

Answer 3

What is Ag? What's the other number for?