Asked by Anonymous
how do you find the standard form of
7(cos255degrees + isin255degrees) ?
7(cos255degrees + isin255degrees) ?
Answers
Answered by
Reiny
we need cos 225° and sin225°
225 = 180+45 , it is in quadrant III and has the same numerical trig values as 45°, but in III both the sine and cosine are negative
sin 225 = - sin 45° = -1/√2
cos 225 = - cos 45° = -1/√2
so 7(cos255degrees + isin255degrees)
= 7(-1/√2 - i (1/√2))
= -7/√2 - (7/√2) i
225 = 180+45 , it is in quadrant III and has the same numerical trig values as 45°, but in III both the sine and cosine are negative
sin 225 = - sin 45° = -1/√2
cos 225 = - cos 45° = -1/√2
so 7(cos255degrees + isin255degrees)
= 7(-1/√2 - i (1/√2))
= -7/√2 - (7/√2) i
Answered by
Steve
now, just change all those 225's to 255's and redo the calculations.
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