Asked by chantal
A procedure calls for 100ml of 20% H2SO4, SG=1.14. How much of the concentrated acid (98%), SG=1.84, must be diluted with water to prepare 100ml of acid of the required strength?
Answers
Answered by
DrBob222
M of the diluted stuff is
1.14 g/mL x 1000 mL x 0.20 x 1/98 = 2.33M
M of the strong stuff is
1.84 x 1000 x 0.98 x 1/98 = 18.4M
Then use the dilution formula.
mLA x MA = mLB x MB
100 x 2.33 = mLB x 18.4M
Solve for mL B. I obtained approx 13 mL
1.14 g/mL x 1000 mL x 0.20 x 1/98 = 2.33M
M of the strong stuff is
1.84 x 1000 x 0.98 x 1/98 = 18.4M
Then use the dilution formula.
mLA x MA = mLB x MB
100 x 2.33 = mLB x 18.4M
Solve for mL B. I obtained approx 13 mL
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.