Asked by Kiley
The information below shows properties of aluminum (Al).
DELTAHfus = 10.07 kJ/mol
DELTAHvap = 225 kJ/mol
Which quantity of heat is required to melt a 342.9-g sample of Al?
127.98 kJ
214.93 kJ
2,851.95 kJ
3,453.00 kJ
DELTAHfus = 10.07 kJ/mol
DELTAHvap = 225 kJ/mol
Which quantity of heat is required to melt a 342.9-g sample of Al?
127.98 kJ
214.93 kJ
2,851.95 kJ
3,453.00 kJ
Answers
Answered by
DrBob222
q = mass Al x heat fusion
Note that mass is in grams and heat fusion is in kJ/mol; therefore, you must convert g Al to mol or heat fusion from kJ/mol to kJ/g
Note that mass is in grams and heat fusion is in kJ/mol; therefore, you must convert g Al to mol or heat fusion from kJ/mol to kJ/g
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