Asked by fizz
if 5^x 25^2y = 1 and 3^5x 9^y= 1/9,find the value of x and y.
Answers
Answered by
Steve
5^x 25^2y = 1
5^x 5^4y = 1
5^(x+4y) = 1
x+4y = 0
3^5x 9^y = 1/9
3^5x 2^2y = 3^-2
5x+2y = -2
x = -4/9
y = 1/9
5^x 5^4y = 1
5^(x+4y) = 1
x+4y = 0
3^5x 9^y = 1/9
3^5x 2^2y = 3^-2
5x+2y = -2
x = -4/9
y = 1/9
Answered by
fizz
if (-2 1 x+2 )
(3 x-4 5 ) =25
(0 1 3 )
a) find the value of x
b) hence ,find (-2 1 x+2 )^-1
( 3 x-4 5 )
(o 1 3 )
p/s : all the value above IS COMBINE in one bracket ( )
(3 x-4 5 ) =25
(0 1 3 )
a) find the value of x
b) hence ,find (-2 1 x+2 )^-1
( 3 x-4 5 )
(o 1 3 )
p/s : all the value above IS COMBINE in one bracket ( )
Answered by
fizz
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