Asked by Jones
Write a nuclear equation for the indicated decay of each of the following nuclides.
Th−234 (beta)......no clue
O−15 (positron emission): 16/8 O-->16/7N + B+ (said was wrong)
Ar-37: 37/18Ar + e ---> 37/17Cl + v (said was wrong)
what would be the proper equations?
Th−234 (beta)......no clue
O−15 (positron emission): 16/8 O-->16/7N + B+ (said was wrong)
Ar-37: 37/18Ar + e ---> 37/17Cl + v (said was wrong)
what would be the proper equations?
Answers
Answered by
DrBob222
Following my post above.
atomic number on left, element in middle, mass number on right. Left numbers must add up on both side; right numbers must add up on both sides. So for Th we write 90Th234 ==> beta + ?
beta is an electron which is -1e0.
90Th234 ==> -1e0 + AXZ
So 90 = -1 + A and A must be 90 + 1 = 91
234 = 0 + Z so Z must be 234
The element which has atomic number 91 is Pa so the full equation is
90Th234 ==> -1e0 + 91Pa234.
The others are done the same way. I'll be glad to check your answers.
atomic number on left, element in middle, mass number on right. Left numbers must add up on both side; right numbers must add up on both sides. So for Th we write 90Th234 ==> beta + ?
beta is an electron which is -1e0.
90Th234 ==> -1e0 + AXZ
So 90 = -1 + A and A must be 90 + 1 = 91
234 = 0 + Z so Z must be 234
The element which has atomic number 91 is Pa so the full equation is
90Th234 ==> -1e0 + 91Pa234.
The others are done the same way. I'll be glad to check your answers.
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