Asked by Anonymous
Zn(s)+2HCl(aq) ->ZnCl2(aq)+Hx(g)
How many millilters of 2.50M HCl(aq) are required to react with 3.95 of Zn(s)?
How many millilters of 2.50M HCl(aq) are required to react with 3.95 of Zn(s)?
Answers
Answered by
DrBob222
mols Zn = grams/atomic mass = ?
mols HCl = twice that (from the coefficients in the balanced equation).
M HCl = mols HCl/L HCl. You know M and mols, solve for L HCl and convert to mL.
mols HCl = twice that (from the coefficients in the balanced equation).
M HCl = mols HCl/L HCl. You know M and mols, solve for L HCl and convert to mL.
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