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Annual sales (in millions of units) of pocket computers are expected to grow in accordance with the following function where t...Question
Annual sales (in millions of units) of pocket computers are expected to grow in accordance with the following function where t is measured in years, with t = 0 corresponding to 1997.
f(t) = 0.18t^2 + 0.16t + 2.64
How many pocket computers will be sold over the 2 year period between the beginning of 1997 and the end of 1998?
NOTE: I got 1.04 but it says it is wrong.
f(t) = 0.18t^2 + 0.16t + 2.64
How many pocket computers will be sold over the 2 year period between the beginning of 1997 and the end of 1998?
NOTE: I got 1.04 but it says it is wrong.
Answers
Steve
Hmmm. we have
∫[0,2] 0.18t^2 + 0.16t + 2.64
= 0.06t^3 + 0.08t^2 + 2.64t [0,2]
= .48 + .32 + 5.28
= 6.08
What did you do to arrive at your answer?
1.04 is obviously way off, since f(0) = 2.64 just to start with.
∫[0,2] 0.18t^2 + 0.16t + 2.64
= 0.06t^3 + 0.08t^2 + 2.64t [0,2]
= .48 + .32 + 5.28
= 6.08
What did you do to arrive at your answer?
1.04 is obviously way off, since f(0) = 2.64 just to start with.
Anonymous
I did my math wrong, I don't know what I was thinking. Thanks for your help.