Asked by hyuyre
At time t = 1,a particle is located at position (x, y) = (4, 3).
If it moves in the velocity field
F(x, y) = xy − 2, y^2 − 11
find its approximate location at time
t = 1.06
(x, y) = ?
If it moves in the velocity field
F(x, y) = xy − 2, y^2 − 11
find its approximate location at time
t = 1.06
(x, y) = ?
Answers
Answered by
Hog Rider
Inferno Dragon
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