Question
What mass of octane must be burned in order to liberate 5410 kJ of heat?
Answers
DrBob222
Do you have the heat of combustion? If not you can calculate it this way.
2C8H18 + 25O2 ==> 16CO2 + 18H2O
dHrxn = dH combustion = (n*dHo formation products) - n*dHo reactants).
So you will obtain that many kJ for 228 g octane. Convert that to grams needed for 5410 kJ.
Post your work if you get stuck.
2C8H18 + 25O2 ==> 16CO2 + 18H2O
dHrxn = dH combustion = (n*dHo formation products) - n*dHo reactants).
So you will obtain that many kJ for 228 g octane. Convert that to grams needed for 5410 kJ.
Post your work if you get stuck.