Asked by Kira
Medical research indicates that the risk of having a car accident increases exponentially as the concentration of alcohol in the blood increases. The risk is modeled by
R=6e^12.77x
Where x is the blood alcohol concentration and R, given as a percent, is the risk of having a car accident. What blood alcohol concentration corresponds to 20% risk of a car accident?
R=6e^12.77x
Where x is the blood alcohol concentration and R, given as a percent, is the risk of having a car accident. What blood alcohol concentration corresponds to 20% risk of a car accident?
Answers
Answered by
Reiny
you are solving
6 e^12.77x = 20
e^12.77x = 10/3
ln both sides and use rules of logs
12.77x lne = ln(10/3) , recall that ln e = 1
x = ln(10/3) /12.77
= appr .094
6 e^12.77x = 20
e^12.77x = 10/3
ln both sides and use rules of logs
12.77x lne = ln(10/3) , recall that ln e = 1
x = ln(10/3) /12.77
= appr .094
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