Question

points Q (10,8) and R (24,10) are the endpoints of a diameter of a circle centered at P. Line l is tangent to the circle at S (12,14). What is the y-intercept of line l?

Answer 1

centre of circle is (17,9)
so slope of radius to tangent = (14-9)/(12-17) = 5/-5 = -1
so the slope of the tangent is +1 (the negative reciprocal)

equation of tangent:
y-14 = +1(x-12)
y = x - 12 + 14
y = x + 2

the y-inercept is 2