Question

A and B are positive acute angles. if sin A=4/5 and cos B=8/17 find the value of tan (A-B)

is the answer =43/100

11 years ago

cosA = 3/5
sinB = 15/17

tanA = 4/3
tanB = 15/8

tan(A-B) = (tanA-tanB)/(1+tanAtanB)
= (4/3 - 15/8)/(1+(4/3)(15/8))
= (-13/24)/(7/2)
= -13/84

11 years ago

thanks

11 years ago

Related Questions

A and B are positive acute angles. If sin A=(3/5) and cosB= (12/13) find the value of sin (A+B) A right triangle has acute angles measuring 2x+6 degrees and 3x-26 degrees. Use the triangle sum the... A right triangle has acute angles measuring (2x+6) degrees and (3x+14) degrees. Use the Triangle Ang... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle Ang... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle Angle S... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle Angle S... A right triangle has acute angles measuring 2x + 6° and 3x - 26° using the triangle angle sum theore... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle... A right triangle has acute angles measuring 2x+6 degrees and 3x−26 degrees. Use the Triangle Angle...