What would be the final temperature of a mixture of 50 g{\rm g} of 17∘C^\circ C water and 50 g{\rm g} of 44∘C^\circ C water?

Question

I have no clue where I should even begin please help.

Answer 1

The sum of the heats gained is zero.

HeatONE+HeatTWO=0
50*c*(Tf-17)+50*c*(Tf-44)=0
c divides out, solve for Tf. Actually, 50 divides out, so Tf= (17+44)/2