Asked by Kimmie
What would be the final temperature of a mixture of 50 g{\rm g} of 17∘C^\circ C water and 50 g{\rm g} of 44∘C^\circ C water?
I have no clue where I should even begin please help.
I have no clue where I should even begin please help.
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
HeatONE+HeatTWO=0
50*c*(Tf-17)+50*c*(Tf-44)=0
c divides out, solve for Tf. Actually, 50 divides out, so Tf= (17+44)/2
HeatONE+HeatTWO=0
50*c*(Tf-17)+50*c*(Tf-44)=0
c divides out, solve for Tf. Actually, 50 divides out, so Tf= (17+44)/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.