Your town is installing a fountain in the main square. If the water is to rise 16 m (52.5 feet) above the fountain, how much pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air? Assume atmospheric pressure equal to 100,000 Pa.

Answer 1

assuming no energy loss through the nozzle, which is a silly assumption...

energy to raise water to 16m...

Force*distance=energy= mgh
netpressure*area*distance=mgh
(P-100kN/m^2)*areastream*16m=areastream*16m*densitywater*g*16m
(P-100kN/m^2)=16*densitywater*9.8N/kg

P=16m*1E6kg/m^3*9.8N/kg +100kPa

Answer 2

495