Asked by apare
A kite is 40ft high, with 50ft of cord out. If the kite moves horizontally at 5min per hour directly away from the boy flying it, how fast is the cord being paid out.
Answers
Answered by
Reiny
let the length of the chord be y
let the horizontal distance of the kite be x ft
given: dx/dt = 5 ?? (looks like a typo in the units)
I will assume you meant:
5 mph = 5280 ft/60 min = 88 ft/min
y^2 = x^2 + 40^2
when y = 50
50^2 = x^2 + 40^2
x = 30
2y dy/dt = 2x dx/dt
dy/dt = 2x dx/dt / 2y
= (x/y)dx/dt
= (30/50)(5) ft/min
= 3 ft/min
( looks quite slow, check my arithmetic)
let the horizontal distance of the kite be x ft
given: dx/dt = 5 ?? (looks like a typo in the units)
I will assume you meant:
5 mph = 5280 ft/60 min = 88 ft/min
y^2 = x^2 + 40^2
when y = 50
50^2 = x^2 + 40^2
x = 30
2y dy/dt = 2x dx/dt
dy/dt = 2x dx/dt / 2y
= (x/y)dx/dt
= (30/50)(5) ft/min
= 3 ft/min
( looks quite slow, check my arithmetic)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.