Asked by hulune
A 100 kg granite rock has been sitting in direct sunlight for 3 hours. It has absorbed 4.5x10^5 calories through its exposure to the sun. If it is now at a temp. of 50 Celsius, what was its temp. initially? (stone(granite) Specific heat in calories per gram degC is 0.19
Answers
Answered by
Damon
sh in cal/kg deg C = .19 *1000 = 190
heat in = mass * sh * delta T
450,000 = 100 * 190 * (50-T)
23.68 = 50-T
T = 26.3 deg C
heat in = mass * sh * delta T
450,000 = 100 * 190 * (50-T)
23.68 = 50-T
T = 26.3 deg C
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