Asked by jooey

If for the pipe carrying water in a building, h = 220 meters, v_1 = 3.8 m/s, and the cross-sectional area at 1 is twice that at 2.

What must P_1 be in order that P_2 = 135000 Pa?
P_1 =

Answers

Answered by bobpursley
Wondering where P1 is?
Answered by Anonymous
at the bottom
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