## Interpretation #1 : Slant height is the edge of the pyramid

Consider the right-angled (internal) triangle formed by the height , half the diagonal of the base and hypotenuse being the slant height.

let the slant height be x

let the diagonal of the base be d

d^2 = 1^2 + 12^2 = 288

d^2 = 288

d = 12âˆš2

d/2 = 6âˆš2

then x^2 = (d/2)^2 + 8^2 = 72 + 64 = 136

x+ âˆš136 = 2âˆš34 or appr 11.66

Interpretation #2 : slant height is the altitude of one of the triangles:

Consider one of the triangles whose base runs from the centre of the pyramid to the midpoint of a base side, with height 8 and hypotenuse as your "slant height"

base = 6

slant height = hypotenuse = y

height =8

where y^2 = 8^2 + 6^2 = 100

y = âˆš100 = 10

Check: notice I can obtain the edge length from this as well

x^2 = y^2 + 6^2

x^2 = 100+36 = 136

x = âˆš136 (same as above)