Asked by Renee

How much energy is required to change a 40 g ice cube from ice at -25°C to steam at 105°C?

11 years ago

Answered by Damon

40 g = .04 kg

.04 [25 (sh ice) + heat of fusion + 100 (sh water) + heat of vaporization + 5 (sh water vapor at 1 atm) ]

11 years ago

Answered by Renee

I don't know if this is right that i pulled in..but i got it wrong. Please help.

4(2090)+(3.33⋅10^5 )+100(4186)+(2.26⋅10^6)+5(4186)

11 years ago

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