Asked by Chemistry
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What is Kp for the reaction below, if Kc = 1.13e-3 at 111.2°C?
4A(s) + 5B(g) ↔ 3C(g)
a. 1.36e-5
b. 1.15e-12
c. 1.14e-6
d. 8.42e-3
What is Kp for the reaction below, if Kc = 1.13e-3 at 111.2°C?
4A(s) + 5B(g) ↔ 3C(g)
a. 1.36e-5
b. 1.15e-12
c. 1.14e-6
d. 8.42e-3
Answers
Answered by
DrBob222
Kp = Kc(RT)<sup>delta n</sup>
where delta n = n products - n reactants
where delta n = n products - n reactants
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