Asked by Chemistry
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For the equilibrium reaction below. To what is Kc equal?
N2(g) + 3H2(g) ↔ 2NH3(g)
a.
[N2] + 3[H2]
------------------
2[NH3]
b.
[N2][H2]3
------------------
[NH3]2
c.
2[NH3]
---------------
[N2]+ 3[H2]
d.
[NH3]2
---------------
[N2][H2]3
For the equilibrium reaction below. To what is Kc equal?
N2(g) + 3H2(g) ↔ 2NH3(g)
a.
[N2] + 3[H2]
------------------
2[NH3]
b.
[N2][H2]3
------------------
[NH3]2
c.
2[NH3]
---------------
[N2]+ 3[H2]
d.
[NH3]2
---------------
[N2][H2]3
Answers
Answered by
DrBob222
P = products
R = reactants
c = coefficients
Kc = (p)^c/(R)^c)
I've seen some text where the products are called RHS (right hand side) and the reactants called LHS (left hand side) then Kc is defined as (RHS)/(LHS) with coefficients becoming exponents.
R = reactants
c = coefficients
Kc = (p)^c/(R)^c)
I've seen some text where the products are called RHS (right hand side) and the reactants called LHS (left hand side) then Kc is defined as (RHS)/(LHS) with coefficients becoming exponents.
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