Asked by roger
A series RLC circuit is made with a C=100pF capacitor, an L=100μH inductor, and an R=30Ω resistor. The circuit is driven at 5×106rad/s with a 1V amplitude. What is the current oscillation amplitude in amps
Answers
Answered by
Henry
Freq. = 5*10^6rad/s * 1rev/6.28rad =
7.958*10^5 rev/s = 7.958*10^5 Hz.
Xl = WL = (6.28*7.958*10^5)*100*10^-6 =
500 Ohms.
Xc=1/WC = 1/(6.28*7.958*10^5)*100*10^-12
= 2000 Ohms.
Z = R + j(Xl-Xc) = 30 + j(500-2000) =
30 - j1500 = 1500.3Ohms [-88.9o]
I = V/Z = 1.0[0o]/1500.3[-88.9] =
6.67*10^-4 Amps.
7.958*10^5 rev/s = 7.958*10^5 Hz.
Xl = WL = (6.28*7.958*10^5)*100*10^-6 =
500 Ohms.
Xc=1/WC = 1/(6.28*7.958*10^5)*100*10^-12
= 2000 Ohms.
Z = R + j(Xl-Xc) = 30 + j(500-2000) =
30 - j1500 = 1500.3Ohms [-88.9o]
I = V/Z = 1.0[0o]/1500.3[-88.9] =
6.67*10^-4 Amps.
Answered by
Hhjj
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