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Skeletal remains had lost 81% of the C-14 they originally contained. Determine the approximate age of the bones. (Assume the ha...Asked by Vanessa
Skeletal remains had lost 84% of the C-14 they originally contained. Determine the approximate age of the bones. (Assume the half life of carbon-14 is 5730 years. Round your answer to the nearest whole number.)
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Answered by
Steve 2.0
(1/2)^t/5730 = .16
t/5730 = log(.16)/log(.5)
t = 5730*log(.16)/log(.5)
t = 15149
makes sense. 12.5% left would be three half-lives, or 17190 years
t/5730 = log(.16)/log(.5)
t = 5730*log(.16)/log(.5)
t = 15149
makes sense. 12.5% left would be three half-lives, or 17190 years
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