Question

A brass ring of diameter 10.00 cm at 22.2°C is heated and slipped over an aluminum rod of diameter 10.01 cm at 22.2°C. Assume the average coefficients of linear expansion are constant.

(b) What if the aluminum rod were 9.16 cm in diameter?

Answer 1

nitial area:A=πd24 =π(10)24 =25π cm2Coefficient of areal expansion:β=2α =2×1.8 =3.6×10−5Change in temperature:△t=50oCIncrease in area:△A=βA△t =(3.6×10−5)(25π)(5