Asked by TT
Solve for u:
u − 2/
u − 4
+ 6 = u +
u − 6/
4 − u
u − 2/
u − 4
+ 6 = u +
u − 6/
4 − u
Answers
Answered by
Steve
If you mean
(u-2)/(u-4) + 6 = u + (u-6)/(4-u)
multiply by u-4 to clear the fractions:
(u-2) + 6(u-4) = u(u-4) - (u-6)
u-2+6u-24 = u^2-4u-u+6
u^2 - 12u + 32 = 0
(u-4)(u-8) = 0
u = 4 or 8
But, u=4 is not allowed, because the original equation divided by (u-4). So, the only solution is u=8.
(u-2)/(u-4) + 6 = u + (u-6)/(4-u)
multiply by u-4 to clear the fractions:
(u-2) + 6(u-4) = u(u-4) - (u-6)
u-2+6u-24 = u^2-4u-u+6
u^2 - 12u + 32 = 0
(u-4)(u-8) = 0
u = 4 or 8
But, u=4 is not allowed, because the original equation divided by (u-4). So, the only solution is u=8.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.