Asked by sage
Find the lenght of the arc from t : 2 to t : 6 for x : 5t-3.y : 1 -3t, z : 4t 5.
Answers
Answered by
Steve
dx = 5 dt
dy = -3 dt
dz = 4 dt
ds = √((dx)^2 + (dy)^2 + (dz)^2)
plug in the values and integrate. (fix the typos first, though)
dy = -3 dt
dz = 4 dt
ds = √((dx)^2 + (dy)^2 + (dz)^2)
plug in the values and integrate. (fix the typos first, though)
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