When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has increased to 10°C. (Round the answers to two decimal place.)
(a) What is the temperature of the drink after 60 minutes?
(b) When will its temperature be 12°C?
a) (5 - 20)e^(-0.0162t) + 20
At 60 minutes it is (-15)e^(-0.0162*60) + 20 = 14.325
b) 12 = (-15)e^(-0.0162t) + 20
-8 = -15e^(-0.0162t)
ln(8/15) = -0.0162t
t = (1/0.0162)*ln(15/8) = 38.8 minutes
1 answer
looks like you are using Newton's Formula for Cooling properly.
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