Asked by Gabby
If an object is dropped from a height of 200 feet, the function h(t)=-16t^2+200 gives the height of the object after t seconds. Approximately, when will the object hit the ground? (1 point)
Answers
Answered by
Steve
just solve for h=0.
-16t^2 + 200 = 0
16t^2 = 200
t^2 = 25/2
. . .
-16t^2 + 200 = 0
16t^2 = 200
t^2 = 25/2
. . .
Answered by
Anonymous
The quadratic formula would also work here, right?
Answered by
Tragic Beauty
C. 3.54 seconds
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