Question
Assume that 0.0200 mole of a gas is collected in the lab by water displacement. If the
temperature of the gas is 26.0oC and the total pressure in the gas tube is 745 mm Hg (including water
vapor), what is the volume in liters of the dry gas? (Use the ideal gas law.)
temperature of the gas is 26.0oC and the total pressure in the gas tube is 745 mm Hg (including water
vapor), what is the volume in liters of the dry gas? (Use the ideal gas law.)
Answers
DrBob222
Ptotal = pH2O + pgas
745 mm = pH2O(look up vapor pressure H2O @ 26 C) + pgas. Solve for pgas which is the pressure of the DRY gas.
Then PV = nRT. You know P (use pressure of dry gas), n, R, and T; solve for V in liters.
745 mm = pH2O(look up vapor pressure H2O @ 26 C) + pgas. Solve for pgas which is the pressure of the DRY gas.
Then PV = nRT. You know P (use pressure of dry gas), n, R, and T; solve for V in liters.