Asked by Renee

Water flowing through a garden hose of diameter 2.77 cm fills a 25.0-L bucket in 1.40 min.

(a) What is the speed of the water leaving the end of the hose?
Answer in m/s

(b) A nozzle is now attached to the end of the hose. If the nozzle diameter is one-third the diameter of the hose, what is the speed of the water leaving the nozzle?
Answer in m/s
Last person that answered got the wrong answers (41.18 & 371).
I'm so lost
Answered by Damon
Well, figure out what I did wrong. (I think nothing)
Answered by Damon
I did this twice and do not see errors. Did I make some stupid mistake?
Answered by Renee
I'm not trying to be mean or anything. The WebAssign website said the answers was wrong.
Answered by Damon
Well, it is their word against mine I guess, but check my arithmetic and units carefully
Physics - Damon, Sunday, March 30, 2014 at 7:21pm

25 L = 25 * 10^-3 m^3
2.77 cm = .0277 m
1.4 min = 84 seconds

flow rate * time = amount
pi r^2 v * 84 = .025 m^3
pi (.0139)^2 v = .025
v = 41.18 m/s

if 1/3 diameter then 1/9 of area so speed is nine times original
371 m/s
Answered by Damon
call 41.18 41.2 maybe, sometimes they fuss about their round off rules.
Answered by Renee
The conversions are correct and I'm getting the same answer using your method, but it's still saying that they are incorrect. Sorry for bothering you so much...
Answered by Damon
I can not find an error. I hope one of the other math/physics teachers finds something.
Answered by Renee
Thanks for helping!!
Answered by Damon
I know the flow rate is the speed times the area. That is my field :)
Answered by Damon
You are welcome :) Good luck. Come back and tell me when you find out.
Answered by Renee
ok. Should I post it again?
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