Asked by shashank
Two positive charges of 12 µC and 8 µC respectively are 10 cm apart. Find the work done in bringing them 4 cm closer, so that, they are 6 cm apart..
Answers
Answered by
bobpursley
find the difference in PE in the two locations.
Hold one charge stationary.
PEtotal= kQQ/.1
PE(new total)=KQQ/.06
subtract the first from the second, that must equal the work done.
There are more difficult ways to work this, involving finding work in an integral calculus equation (work= INT force*dr)
Hold one charge stationary.
PEtotal= kQQ/.1
PE(new total)=KQQ/.06
subtract the first from the second, that must equal the work done.
There are more difficult ways to work this, involving finding work in an integral calculus equation (work= INT force*dr)
Answered by
anamika
5.8 j
Answered by
Anonymous
4.8J
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