Asked by David
Determine the moment of inertia of a 11.1kg sphere of radius 0.794m when the axis of rotation is through its center.
Answers
Answered by
Damon
I = (2/5) m r^2
= (2/5)(11.1)(.630)
= 2.8 kg m^2
= (2/5)(11.1)(.630)
= 2.8 kg m^2
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