Asked by Christina
Suppose we take a 1 m long uniform bar and support it at the 27 cm mark. Hanging a 0.31 kg mass on the short end of the beam results in the system being in balance. Find the mass of the beam.
Answers
Answered by
Damon
clockwise moments about support (ignoring g which cancels)
(50 - 27) m - 27(.31) = 0
23 m = 8.37
m = 0.364
(50 - 27) m - 27(.31) = 0
23 m = 8.37
m = 0.364
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