Asked by h
The density of 19.0% by mass of nitric acid, HNO3 is 1.11 g cm-3. Calculate the
volume (dm3) of acid needed to prepare 2.00 dm3 of 3.00 mol dm-3 HNO3
solution. (FW HNO3 = 63 g/mol)
volume (dm3) of acid needed to prepare 2.00 dm3 of 3.00 mol dm-3 HNO3
solution. (FW HNO3 = 63 g/mol)
Answers
Answered by
DrBob222
First determine the concn of HNO3 in the 19.0% stuff.
1.11 g/cc x 1000 cc x 0.19 x (1 mol/98 g) = estimated 2 mol/dm^3
Then use the dilution formula of
c1v1 = c2v2
2*v = 2*3
Solve for v = approx 3 dm^3
Remember to recalculate all of the above.
1.11 g/cc x 1000 cc x 0.19 x (1 mol/98 g) = estimated 2 mol/dm^3
Then use the dilution formula of
c1v1 = c2v2
2*v = 2*3
Solve for v = approx 3 dm^3
Remember to recalculate all of the above.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.