Question
Two buildings are separated by an alley. Joe is looking out of a window 60 feet above the ground in one building. He observes the measurement of the angle of depression of the base of the second building to be 50 degrees and the angle of elevation of the top to be 40 degrees. How high, to the nearest foot, is the second building?
Answers
width of alley = 60 tan 40
so second building = 60 + 60 tan^2 40
=60 (1 + tan^2 40) = 110 ft
so second building = 60 + 60 tan^2 40
=60 (1 + tan^2 40) = 110 ft
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