Asked by Libby
in triangle PQR, PQ=5.4, QR=3.6, and PR=6.2. to the nearest tenth, what is m<R?
Answers
Answered by
Reiny
cosine law ....
5.4^2 = 6.2^2 + 3.6^2 - 2(6.2)(3.6)cosR
cosR = 22.24/44.64
= .4982..
R = 60.1°
5.4^2 = 6.2^2 + 3.6^2 - 2(6.2)(3.6)cosR
cosR = 22.24/44.64
= .4982..
R = 60.1°
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