(Weighing produce). A supermarket has three employees who package and weigh produce. Employee A records the correct weight 98% of the time. Employees B and C record the correct weight 97% and 95% of the time, respectively. Employees A, B, and C handle 40%, 40% and 20% of the packaging, respectively. A customer complains about the incorrect weight recorded on a package he has purchased. What is the probability that the package was weighed by employee C?
2 answers
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Math - Damon, Thursday, March 27, 2014 at 11:57am
A wrong .02 * .4 = .008
B wrong .03 * .4 = .012
C wrong .05 * .2 = .01
total wrong = .03
C wrong/total wrong = .01/.03 = .33
A wrong .02 * .4 = .008
B wrong .03 * .4 = .012
C wrong .05 * .2 = .01
total wrong = .03
C wrong/total wrong = .01/.03 = .33
1 answer