Asked by Annabelle

The principal quantum number, n, describes the energy level of a particular orbital as a function of the distance from the center of the nucleus. Additional quantum numbers exist to quantify the other characteristics of the electron. The angular momentum quantum number (ℓ), the magnetic quantum number (mℓ), and the spin quantum number (ms) have strict rules which govern the possible values. Identify allowable combinations of quantum numbers for an electron. Select all that apply.

1) n=3, l=-2, m(l)= -1, ms= +1/2
2) n = 3, ℓ= 3, mℓ= 1, ms= –1/2
3) n = 2, ℓ= 1, mℓ= 0, ms= 1
4) n = 4, ℓ= 0, mℓ= 1, ms= –1/2
5) n = 5, ℓ= 4, mℓ= 0, ms= –1/2
6) n = 3, ℓ= 2, mℓ= –1, ms= 1/2

I thought 4,5 and 6 were right but it says I am wrong.

Answers

Answered by Damon
3) is out, spin is =/- 1/2

1) is out, negative L

2) is out , biggest L is n-1 or 2

4) is out, with L=0 you only have +/- 1/2 for spin, no ml - 1

5) looks possible

6) looks possible
Answered by Annabelle
but on 4 the spin is Ms= -1/2
Answered by Damon
4 is out because with L = 0 you have no choice of ml = 1.
wtih L = 0
ml = 0
and spin can be 1/2 or -1/2

ml = 1 is not allowed if L = 0
Answered by DrBob222
The problem with 4 is not the +/- 1/2, you can't have ml of one with ell = 0
m ell values are + ell to -ell. If ell = 0, you may have m ell of zero only. Can't be + one.
Answered by Damon
ml ranges from -L to +L
If L = 0, ml = 0
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