L = w+5
2 L + 2 w = 66 or L + w = 33
so
w + 5 + w = 33
2 w = 28
w = 14 etc
The length of a rectangle is 5 meters more than its width. The perimeter is 66 meters. Find the length and the width of the rectangle
2 answers
P = 2L + 2W
66 = 2(w + 5) + 2W
66 = 4W + 10
56 = 4W
14 = W
66 = 2(w + 5) + 2W
66 = 4W + 10
56 = 4W
14 = W