A series circuit contains only a resistor and an inductor. The voltage V of the generator is fixed. If R = 15 and L = 5.6 mH, find the frequency at which the current is one-half its value at zero frequency. ?? Hz

Question

Thanks!

Answer 1

the cutoff frequency is r/(2pi L) = 15/(2pi*5.6 * 10^-3) = 426 Hz