Asked by Please help
Solve by substitution:
x-y=3
x+3y=6
This is what I get:
X+3y=6
Y=x-3
X(x-3)=6
2x= 9
2 2
X= 9/2
9/2+3y=6
9/2-9/2+3y= 6-9/2
3y/3= 3/2/3
Y= ½
x-y=3
x+3y=6
This is what I get:
X+3y=6
Y=x-3
X(x-3)=6
2x= 9
2 2
X= 9/2
9/2+3y=6
9/2-9/2+3y= 6-9/2
3y/3= 3/2/3
Y= ½
Answers
Answered by
Steve
man, ya gotta check your answer. It does not fit the first equation.
y = x-3, so
x + 3(x-3) = 6
4x = 15
x = 15/4
y = 3/4
y = x-3, so
x + 3(x-3) = 6
4x = 15
x = 15/4
y = 3/4
Answered by
Please help
thank you
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