Asked by Alice
if f(x)=1-3x and g(x)=x^2-1, find :
f(g(x))
f(g(x))
Answers
Answered by
Henry
Given: F(x) = 1 - 3x. g(x) = x^2 - 1.
F(g(x)) = F(x^2-1)
F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 =
-3x^2 + 4
F(g(x)) = -3x^2 + 4
F(g(x)) = F(x^2-1)
F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 =
-3x^2 + 4
F(g(x)) = -3x^2 + 4
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