Asked by kait
The decomposition of hydrogen iodide on a gold surface at 150 oC
HI(g) ½ H2(g) + ½ I2(g)
is zero order in HI with a rate constant of 1.20E-4 Ms-1.
If the initial concentration of HI is 0.575 M, the concentration of HI will be 0.116 M after seconds have passed.
HI(g) ½ H2(g) + ½ I2(g)
is zero order in HI with a rate constant of 1.20E-4 Ms-1.
If the initial concentration of HI is 0.575 M, the concentration of HI will be 0.116 M after seconds have passed.
Answers
Answered by
DrBob222
A = Ao - kt
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