Asked by roger

Suppose the average body temp is 98.6 assume the variable is normally distributed with a standard deviation of .74 degrees. suppose a sample of 100 is taken. what is the probability that the mean is below 98.4??? Between 98.5 AND 98.7??

Answers

Answered by Kuai

z = (98.5-98.6)/.74/sqr(100)


z = (98.7- 98.6)/.74/sqr(100)
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions