Asked by Eiban
A ball is traveling down a straight track at 20 m/s. How fast will the ball's speed be after it climbs a hill in the track that is 15 m high?
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h
V^2 = 20^2 - 19.6*15 = 106
V = 10.30 m/s.
V^2 = 20^2 - 19.6*15 = 106
V = 10.30 m/s.
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