Six of one but all roads lead to the same answer.
You start with 0.01M NaOH and you dilute it from 50 to 100 which is a factor of 2.
0.01/2 = 0.005M OR
0.01M x (100/200) = 0.005 OR
mols NaOH = M x L = 0.01M x 0.05L = 0.0005 mols and M = mols/L = 0.0005/0.1L = 0.005M (50 mL + 50 mL = 100 mL = 0.1L)
Voila!
The reaction OH- + NH4+ = H20 + NH3 is kinetically first order in both reactants' concentrations. The rate constant is 2e10 1/M s. If 50 ml of .01 M NaOH is mixed with 50 ml of .01 M NH4CL, find the time required for the OH- concentration to reach 1e-4 M.
Your answer: It starts at 0.01/2 = 0.005 and you want it to go to 1E-4
ln(5E-3/1E-4) = 2E10*t
Solve for t.
My new question is: Why do you divide .01 by 2. Shouldn't you divide by 1 because 50ml+50ml=1L
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