Asked by Matt
A voltaic cell is constructed that uses the following reaction and operates at 298 K: 2 Al(s) + 3 Mn2+(aq) 2 Al3+(aq) + 3 Mn(s). What is the potential, E, of this cell when [Mn2+] = 0.10 M and [Al3+] = 1.5 M?
Answer:
The EMF of this cell under standard conditions is :
+1.66 V + -1.18 V = 0.48 V
E = 0.48 V ā (0.0592 V / 6 mol e-) (log (1.5)2/(0.10)3) = 0.45 V
Answer:
The EMF of this cell under standard conditions is :
+1.66 V + -1.18 V = 0.48 V
E = 0.48 V ā (0.0592 V / 6 mol e-) (log (1.5)2/(0.10)3) = 0.45 V
Answers
Answered by
DrBob222
This looks ok to me.
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